Question

A golf ball is hit with an initial velocity of 80 ft/sec.Use the equation h(t)=80t-16t^2 where h(t) is the height of the object in feet and t is the time in seconds. How long will it take for the ball to hit the ground?

Answer 1

Answer:

The ball takes 5 seconds to hit the ground

Step-by-step explanation:

The equation to model the height of a golf ball in time t is:

$h(t)=80t-16t^2$

There are two moments when the height is zero: At launch time and when it hits the ground. To find the last time, we equate:

$80t-16t^2=0$

Factoring out t:

$t(80-16t)=0$

It gives us two solutions:

t=0

$80-16t=0$

Solving:

$-16t=-80$

$t=-80/(-16)=5$

t = 5 sec

Thus, the ball takes 5 seconds to hit the ground