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MrRissso [65]
3 years ago
14

Which line has an equation of y=-5x+4 in slope-intercept form?

Mathematics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

Last choice.

Step-by-step explanation:

To find the option that is equivalent to this equation, we can begin by narrowing down our options. The slope contains a negative number, meaning the second point must have a lower y value than the first.

Using this criteria, we can eliminate the first and the third answer. Now, we can test the second and fourth answer.

We can test using the slope formula and plugging in values. When the slope formula: m= \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

We get a slope of -5 for both of these equations. Let's plug in the point values to check whether they work:

Choice 2:

-24 = -5(4) + 4

-24 = -20 + 4

-24 ≠ -16

Choice 4:

-16 = -5(4) + 4

-16 = -20 + 4

-16 = -16

Therefore, choice 4 is correct!

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Answer: Hope it helps...

Step-by-step explanation: mark as an brainliest... if so

6 0
3 years ago
What is StartFraction pi Over 3 EndFraction radians converted to degrees? If necessary, round your answer to the nearest degree.
Oliga [24]

Answer: 60°

Step-by-step explanation:

π/3

Since π is denoted as 180°, the question can be rewritten as:

π/3 .

To convert π/3 radians to the nearest degree will be:

π/3 = 180/3

= 60°

4 0
3 years ago
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MIRCrence.
lianna [129]
Ok so maybe add or subtract the numbers and see what u get :) I calculated it
7 0
3 years ago
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15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
Can someone help me ​
nexus9112 [7]

Answer:

Its C i think

Step-by-step explanation:

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