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Orlov [11]
3 years ago
9

X+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically

x+y+2=-5     equation 1

-2x-y+2=-1    equation 2

x-2y-2=0      equation 3

Add equation 1 + 2+ 3

x+y+2=-5 + -2x-y+2+1 + x-2y-2

x+y+2= -7+2+1-2x+x+y

x+y+2= -4-x+y

x+y+2+4+x-y= 0

2x+6= 0

2x= -6

divide both side by 2

x= -3

from equation 1 insert x

x+y+2=-5

since x=-3

then, -3+2+y= -5

-1+y= -5

y= -5+1

y= -4

Step-by-step explanation:

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Find the inverse function in slope-intercept form (mx+b):<br> f(x)=-x+12
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12 - x

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y = -x + 12

Replace x with y.

x = -y + 12

Solve for y, x = -y + 12

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3 years ago
Dado dos ángulos complementarios, uno mide (2x + 10) y el otro (x + 20),
rusak2 [61]

Answer:

El valor de <em>x</em> es igual a 20 o <em>x</em> = 20.

Step-by-step explanation:

Lo primero que se debe saber es que <em>dos ángulos complementarios suman un ángulo recto o 90º</em>.

Supongamos que el valor de un ángulo \\ \alpha y un ángulo \\ \beta valen:

\\ \alpha = 2x + 10 [1]

\\ \beta = x + 20 [2]

Como la suma de  \\ \alpha + \beta = 90 [3]

Entonces

\\ \alpha + \beta = (2x + 10) + (x + 20) = 90

Sumamos los factores comunes entre si:

\\ (2x + x) + (10 + 20) = 90

Para la primera expresión debemos recordar que se suman sólo los coeficientes. Así:

\\ (2 + 1)x + (10 + 20) = 90

\\ 3x + 30 = 90

Para despejar la incógnita <em>x</em>, debemos tener en cuenta que <em>una igualdad no se altera si se suma, se resta, se multiplica o divide un mismo valor a cada lado de ella</em>. Por esta razón, para despejar 3x, lo primero que podemos hacer es sumar -30 a cada lado de la expresión (lo que es igual a restar 30 a cada lado de la misma). Así tenemos:

\\ 3x + 30 - 30 = 90 - 30

\\ 3x + 0 = 90 - 30

\\ 3x = 60

Ahora dividimos cada miembro de la igualdad entre 3 (o multiplicamos cada lado de la igualdad por \\ \frac{1}{3} ):

\\ \frac{3}{3}x = \frac{60}{3}

Como sabemos que:

\\ \frac{3}{3} = 1

Entonces:

\\ 1*x = \frac{60}{3}

\\ x = \frac{60}{3}

\\ x = 20

De esta manera, el valor de <em>x</em> es igual a 20 o x = 20.

Lo anterior lo podemos comprobar considerando las ecuaciones [1], [2] y [3]. Así tenemos que:

\\ \alpha = 2x + 10 [1]

Sustituimos x por el valor de 20:

\\ \alpha = 2*20 + 10 = 40 + 10 = 50

\\ \beta = x + 20 [2]

Hacemos lo mismo para [2]:

\\ \beta = 20 + 20

\\ \beta = 40

De esta manera:

\\ \alpha + \beta = 90 [3]

\\ 50 + 40 = 90

4 0
3 years ago
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