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Inessa05 [86]
3 years ago
14

Find pb, if pj=14 and jb= 28

Mathematics
2 answers:
sergiy2304 [10]3 years ago
4 0

pj=14

jb=28

p=14/j

b=28/j

pb=(14/j)×28/j

pb=392/j²

j²=9.333≅

pb=392/9.333

pb=42.0015≅42

anyanavicka [17]3 years ago
3 0

Answer:

42

Step-by-step explanation:

Based on the information given, point j is the midpoint, as it is shared by both line segments. Set the equation:

pb = pj + jb

Note:

pj = 14

jb = 28

Plug in the corresponding numbers to the corresponding variables:

pb = pj + jb

pb = 14 + 28

pb = 42

pb = 42 is your answer.

~

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Solve
2
x
+
5
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−
y
=
−
3
x
+
21
−
y
−
1
=
−
3
x
+
21
−
1
(Divide both sides by -1)
y
=
3
x
−
21
Step: Substitute
3
x
−
21
for
y
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2
x
+
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y
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3
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2
x
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y
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2
x
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3
x
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21
)
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17
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3
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17
x
−
105
+
105
=
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3
+
105
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17
x
=
102
17
x
17
=
102
17
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x
=
6
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for
x
in
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=
3
x
−
21
:
y
=
3
x
−
21
y
=
(
3
)
(
6
)
−
21
y
=
−
3
(Simplify both sides of the equation)
Answer:
y
=
−
3
and
x
=
6

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