J(Jane) + 3 = B(Billy)*2
J + 3 = 7(2)
J + 3 = 14
J = 14-3
J = 11 (Jane is 11)Cheers!
Answer:

Step-by-step explanation:
We can model the string as a hypergeometric distribution, as each bit has two possible values, 1 or 0, and the chance of a 1 or 0 changes with every bit, as there are a finite number M of 0's and N of 1's and every bit takes one of those values.
If M+N (total size of the string) >> r (number of trials), we could model it as a binomial distribution as the probability of a 1 or 0 wouldn't change in a significant amount with every bit, but as we don't know the magnitude of M+N and r, we follow up with hypergeometric distribution.
The distribution has the following formula for probability:

Where k is the number of sucesses, K is how many total sucess states are in the population, N is the population size and n is the number of draws.
For our case, a 1 would be a sucess, i.e. k the number of 1's we want to know the probability, N our total number of 1's, M+N the length of the string (population size) and we want to analyse what happens in the first r bits (number of draws):

Answer:
-5/6
Step-by-step explanation:
Slope= y2-y1/x2-x1
The answer would be B because the 100 stays in there and you are adding 8% per year. Hope this helps.
Answer:
<em>(675°F − 32) × 5/9 + 273.15 = 630.372K </em>
Hope it's right if not so sorry :)