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BigorU [14]
3 years ago
15

(1, 0) is an ordered pair of the function f(x) = 1 + x. True False​

Mathematics
1 answer:
Dominik [7]3 years ago
6 0

Answer:

false

Step-by-step explanation:

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HELP!! <br> Find the mean, median, and mode of the data.<br><br><br> mean:<br> median:<br> mode:
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Answer: mean:4 Median: 3 mode:10

Step-by-step explanation:

8 0
3 years ago
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What is the answer 12 x 12
aleksandr82 [10.1K]

12 × 12 would equal to 144

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8 0
3 years ago
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Carrie has 3 times as many green beads as red beads and 2 as many blue beads as green beads if she has 150 total how many green
Vikentia [17]

There are 45 green beads

<em><u>Solution:</u></em>

Let the number of red beads be "x"

Given that, Carrie has 3 times as many green beads as red beads

Number of green beads = 3 times number of red beads

Number of green beads = 3x

<em><u>She 2 as many blue beads as green beads</u></em>

Number of blue beads = 2 times the number of green beads

Number of blue beads = 2(3x) = 6x

<em><u>She has 150 total</u></em>

Therefore,

Number of red beads + Number of green beads + Number of blue beads = 150

x + 3x + 6x = 150

10x = 150

x = 15

Thus, number of green beads = 3x = 3(15) = 45

Thus there are 45 green beads

7 0
4 years ago
List the factor pair of numbers for 48 and 56
levacccp [35]
<span>gcf(48,56) = 8
</span><span>The factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, 1
</span><span>The factors of 56 are 56, 28, 14, 8, 7, 4, 2, 1
</span>The matching factors for 48 and 56 are 1, 2, 4, and 8.  

3 0
3 years ago
A cylindrical can has a volume of 16 cm 3. What dimensions yield the minimum surface​ area? 1. The radius of the can with the mi
kykrilka [37]

Answer:

radius = 1.37 cm

height = 2.71 cm

Step-by-step explanation:

We are given volume = 16 m³.

Formula for volume of a cylinder is;

V = πr²h

Thus,

πr²h = 16

h = 16/πr²

Now formula for the surface area is;

S = 2πr² + 2πrh

Putting 16/πr² for h gives;

S = 2πr² + 2πr(16/πr²)

S = 2πr² + 2π(16/πr)

S = 2π(r² + 16/πr)

To minimize, we will find the derivative of S and equate to zero

S' = 2π(2r - 16/πr²) = 0

4πr - 32/r² = 0

4πr = 32/r²

r³ = 32/4π

r = ∛(32/4π)

r = 1.37 cm

From h = 16/πr²;

h = 16/(π × 1.37²)

h = 2.71 cm

5 0
4 years ago
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