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Ymorist [56]
3 years ago
9

Teaching descriptive statistics. A study compared five different methods for teaching descriptive statistics. The five methods w

ere traditional lecture and discussion, programmed textbook instruction, programmed text with lectures, computer instruction, and computer instruction with lectures. 45 students were randomly assigned, 9 to each method. After completing the course, students took a 1-hour exam.
a. What are the hypotheses for evaluating if the average test scores are different for the different teaching methods?
b. What are the degrees of freedom associated with the F-test for evaluating these hypotheses?
c. Suppose the p-value for this test is 0.0168. What is the conclusion?
Mathematics
1 answer:
irina [24]3 years ago
5 0

Answer:

Step-by-step explanation:

a. The hypotheses are:

Null hypothesis: the average test scores are the same for the different teaching methods.

Alternative hypothesis: the average test scores are different for the different teaching methods.

b. To determine the degree of freedom for the F test: we must find two sources of variation such that we have two variances. The two sources of variation are: Factor (between groups) and the error (within groups) and add this up. Or use (N - 1). N is number in sample

c. With a p value of of 0.0168 and using a standard significance level of 0.05, we will reject the null hypothesis as 0.0168 is less than 0.05 and conclude that the average test scores are different for the different teaching methods.

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7 0
3 years ago
Solve the proportion below. 7/x=19
alexgriva [62]

Answer:

The value of x is approximately 0.3684.

Step-by-step explanation:

Given:

\frac{7}x}=19

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Solution:

Now we can see that;

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Now To make whole number into fraction we will divide by 1.

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19=\frac{19}{1}

Now the new equation will be;

\frac{7}{x}=\frac{19}{1}

Now by cross multiplication we get;

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Now dividing both side by 19 we get;

\frac{7}{19}=\frac{19x}{19}\\\\x\approx0.3684

Hence the value of x is approximately 0.3684.

6 0
4 years ago
The mass of a dust particle is 0.000000000753 kg. How would this number be written in scientific notation? 753 * 10-10 7.53 * 10
Andrei [34K]

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Step-by-step explanation:


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3 years ago
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6 0
3 years ago
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Answer:

The inverse is 5x+3

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The inverse is 5x+3

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