Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
Answer: Could be subdivided into smaller and smaller units.
Explanation:
The continuous data are basically measured in the small units and can be easily subdivided into smaller parts without changing their actual meaning.
The continuous data also contain numeric value and can be divided into smaller and finer meaningful parts.
The continuous data can be measured according to the precision of the system. The size and volume are the example of the continuous data.
Answer:
Know what the code should do
The answer would be
C. It adds visual effects when you move from one slide to another.
Hope this has helped you! :)
Answer:
Explanation:
260 cost units, Big O(n) complexity for a push
