Answer:
The answer is "Option b".
Explanation:
In the given code, a static method "inCommon" is declared, that accepts two array lists in its parameter, and inside the method two for loop is used, in which a conditional statement used, that checks element of array list a is equal to the element of array list b. If the condition is true it will return the value true, and if the condition is not true, it will return a false value. In this, the second loop is not used because j>0 so will never check the element of the first element.
Answer:
#include <iostream>
#include<string.h>
using namespace std;
void printCharacter(string name){
for(int i=0;name[i]!='\0';i++){
cout<<name[i]<<endl;
}
}
int main()
{
string name;
cout<<"enter the name: ";
cin>>name;
printCharacter(name);
}
Explanation:
first include the two libraries iostream for input/output and string library for using the string.
then, create the main function and declare the variable type string.
cout instruction is used o display the message on the screen.
cin is used to store the value in the name variable.
after that, call the function. The program control move to the the function. In the function for loop is used to print the character one by one until end of the name.
Answer:
wear a mask use hand sanitizer dont get in contact with anyone between 6 feet
Explanation:
<span>A pointing device controls the movement of the </span>Mouse Pointer
