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suter [353]
3 years ago
15

What is climacteric​

Biology
1 answer:
Lunna [17]3 years ago
4 0

Answer:  stage of fruit ripening, characterised by a surge of respiratory activity and usually coinciding with full ripeness and flavour in the fruit.

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The pH of the inner thylakoid space has been measured, as have the pH of the stroma and of the cytosol of a particular plant cel
yawa3891 [41]

Answer:

a. the pH within the thylakoid is less than that of the stroma

Explanation:

The pH of thylakoid membrane is 8 at normal conditions but it became highly acidic like 4 during photosynthesis. The electron transport chain utilize the energy released by excited electrons to pump the H+ ions to lumen of thylakoid membrane from stroma during light reaction of photosynthesis. The H+ ions are present in both the stroma and thylakoid membranes. These high potential H+ ions are utilized by ATP synthase complex for the production of ATP.

We know that more the H+ ions lesser will be the pH and lumen have the high concentration of H+ ions. While the pH of stroma is normally kept acidic by plants to create a concentration and potential difference of H+ ions for the production of ATP. That why the lumen have lower pH than stroma of chloroplast.

4 0
3 years ago
Read 2 more answers
how is the knowledge of prokaryotic and Eukaryotic cells beneficial to you for understanding the living organisms better​
tatyana61 [14]

Explanation:

im pretty sure its They ward off disease-causing organisms by competing for space and nutrients on and inside the body. ... Scientists and doctors can even utilize prokaryotes to help the human body. The two key components of ecosystem stability are resilience and resistanc

8 0
3 years ago
What are two variables in determining climate
Monica [59]
Temperature and precipitation
6 0
3 years ago
22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
3 years ago
Item 19
vagabundo [1.1K]

to prevent damage from landslides because construction engineers brace buildings in the earthquake zones

4 0
4 years ago
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