What are the factor of 8x^3 - 27?..
1 answer:
Answer:
(x - 3)(4x² + 6x + 9)
Step-by-step explanation:
This is a difference of cubes which factors in general as
a³ - b³ = (a - b)(a² + ab + b²)
8x³ = (2x)³ ⇒ a = 2x
27 = 3³ ⇒ b = 3
Hence
8x³ - 27
= (2x)³ - 3³
= (2x - 3)( (2x)² + (2x × 3) + 3²)
= (2x - 3)(4x² + 6x + 9)
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I’m not sure if you are allowed to do it that way so I can find other ways if needed
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