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Luda [366]
2 years ago
8

What are the factor of 8x^3 - 27?..

Mathematics
1 answer:
katen-ka-za [31]2 years ago
3 0

Answer:

(x - 3)(4x² + 6x + 9)

Step-by-step explanation:

This is a difference of cubes which factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

8x³ = (2x)³ ⇒ a = 2x

27 = 3³ ⇒ b = 3

Hence

8x³ - 27

= (2x)³ - 3³

= (2x - 3)( (2x)² + (2x × 3) + 3²)

= (2x - 3)(4x² + 6x + 9)

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