What are the factor of 8x^3 - 27?..

Mathematics

1 answer:

katen-ka-za [31]3 years ago

3 0

Answer:

(x - 3)(4x² + 6x + 9)

Step-by-step explanation:

This is a difference of cubes which factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

8x³ = (2x)³ ⇒ a = 2x

27 = 3³ ⇒ b = 3

Hence

8x³ - 27

= (2x)³ - 3³

= (2x - 3)( (2x)² + (2x × 3) + 3²)

= (2x - 3)(4x² + 6x + 9)

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Help me please <br> Surds

kodGreya [7K]

Answer:

12 $\sqrt{6}$ + 8 $\sqrt{15}$ + 12 + 4 $\sqrt{10}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

(4 $\sqrt{3}$ + 2 $\sqrt{2}$ )(3 $\sqrt{2}$ + 2 $\sqrt{5}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

4 $\sqrt{3}$ (3 $\sqrt{2}$ + 2 $\sqrt{5}$ ) + 2 $\sqrt{2}$ (3 $\sqrt{2}$ + 2 $\sqrt{5}$ ) ← distribute both parenthesis

= 12 $\sqrt{6}$ + 8 $\sqrt{15}$ + 12 + 4 $\sqrt{10}$

7 0

3 years ago

Sphere with a volume of 1767.1 . what is the radius?

Llana [10]

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