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ValentinkaMS [17]
2 years ago
9

Multiply. 3(6u)

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
6 0

Answer:

3u+ 18

try that :)

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2/3 - (30 divided by 5) + 9=
irakobra [83]

2^3 - (30 / 5) + 9

8 - (6) + 9

2 + 9

11 is your answer

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3 years ago
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Please help me find the value of X
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Answer:

Is this

Step-by-step explanation:

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Which of the following is not one of the 8th roots of unity?
Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1.  Since z=1=1+0\cdot i, then

Rez=1,\\ \\Im z=0

and

|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.

This gives you \varphi=0.

Thus,

z=1\cdot(\cos 0+i\sin 0).

2. The 8th roots can be calculated using following formula:

\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.

Now

at k=0,  z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;

at k=1,  z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=2,  z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;

at k=3,  z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};

at k=4,  z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;

at k=5,  z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

at k=6,  z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;

at k=7,  z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};

The 8th roots are

\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.

Option C is icncorrect.

5 0
3 years ago
the area of a square poster is 30 in square. Find the length of one side of the poster to the nearest tenth of an inch​
insens350 [35]

Answer:

x = 5.5 (nearest tenth)

Step-by-step explanation:

let x be the length of 1 side

given area of square poster is 30 in²

and

Area = (length of 1 side )²

hence

30 = x²

x = √30

x = 5.4772

x = 5.5 (nearest tenth)

6 0
3 years ago
What is the value of x?
Akimi4 [234]
(2x + 2) = (3x + -52)

Reorder the terms:
(2 + 2x) = (3x + -52)

Remove parenthesis around (2 + 2x)
2 + 2x = (3x + -52)

Reorder the terms:
2 + 2x = (-52 + 3x)

Remove parenthesis around (-52 + 3x)
2 + 2x = -52 + 3x

Solving
2 + 2x = -52 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
2 + 2x + -3x = -52 + 3x + -3x

Combine like terms: 2x + -3x = -1x
2 + -1x = -52 + 3x + -3x

Combine like terms: 3x + -3x = 0
2 + -1x = -52 + 0
2 + -1x = -52

Add '-2' to each side of the equation.
2 + -2 + -1x = -52 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = -52 + -2
-1x = -52 + -2

Combine like terms: -52 + -2 = -54
-1x = -54

Divide each side by '-1'.
x = 54

Simplifying
x = 54
4 0
3 years ago
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