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algol [13]
3 years ago
5

Part 1: Using complete sentences, compare the key features and graphs of sine and cosine. What are their similarities and differ

ences?
Part 2: Using these similarities and differences, how would you transform f(x) = 3 sin(4x - π) + 4 into a cosine function in the form f(x) = a cos(bx - c) + d?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0
Part 1: Similarities of sine and cosine graphs are that both has an amplitude of 1 and a period of 2pi.
A differences between sin and cos graphs includes that sin graph passes through point (0, 0).

The required cosine graph is <span>f(x) = 3 cos(4x - 3π/2) + 4</span>
You might be interested in
Check all that apply. Thanks!
spayn [35]

Answer:

The answers are options C and E

Hope this helps you

8 0
3 years ago
Expand.<br> Your answer should be a polynomial in standard form.<br> (x-3)(x-4)=
nekit [7.7K]

Answer:

Step-by-step explanation:

So, it's x*x+x*-3+-4*x+3*-3

That simplifies to x^2 - 7x + 12

5 0
2 years ago
Which is the real world situation that can be described by a linear inequality
garik1379 [7]

Answer:

Pretty sure it's B

Step-by-step explanation:

Everything else would be more like an equation. I think B is the only inequality.

7 0
3 years ago
Jake sold 36 tickets to the school fair, and Jeanne sold 15 tickets. what is the ratio, in simpliest form, to the number of tick
anzhelika [568]

Answer:

I kinda forgot how to do ratios but i think it would be 12 and 5

Step-by-step explanation

Jake                 Jeanne

36                          15

<em>12</em>                            <em>5</em>


8 0
3 years ago
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
3 years ago
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