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Aleonysh [2.5K]
2 years ago
11

Please help what is the answer its a math question find the lcd!!!

Mathematics
1 answer:
andriy [413]2 years ago
4 0

Step-by-step explanation:

sorry I don't now but when I now I will tell you ok but mybe it 12×12×12

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Evaluate the expression:
Simora [160]
The dot product will have you multiply the corresponding coordinates and add up the products

v dot w = (6*(-7)) + (7*5) + (-3*2)
v dot w = -42 + 35 - 6
v dot w = -7 - 6
v dot w = -13

Answer: -13
6 0
3 years ago
Label and connect the coordinates above
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3 0
2 years ago
Jack took a test and got 13 out of 17 points. He took a make-up test and got 12 out of 15 points.
blagie [28]

Answer:

4.6

Step-by-step explanation:

The answer is 4.6%, hope it helps! sorry if wrong!

3 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Two rigid transformations are used to map triangle JKL to triangle MNQ. The first is a translation of vertex L to vertex Q. What
oee [108]

Answer:

I think it could be D

Step-by-step explanation:

Because if you move point K up a little they will be congruent , I’m not 100% sure tho

7 0
3 years ago
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