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morpeh [17]
3 years ago
10

Jaquez earns money by doing yard work. It takes her an average of 3 hours to pull weeds and an average of 2.5 hours to mow the l

awn. She can work no more than 8 hours a day. She charges $50 to weed and $65 to mow the lawn. She needs to cover her expenses of $120 to make a profit. Write a system of inequalities that would help determine how many flowerbeds and lawns he could complete on a given day. (Note – you do not need to solve, just write the system and label the variables you use).
Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

<5.5 + 120[> underscore}

Step-by-step explanation:

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How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
2 years ago
Which inequality corresponds<br>to the following graph?​
alexira [117]
The first one x is greater than and equal to 34
4 0
3 years ago
PLEASE HELP 4. The Buff City Soaps in Arlington is counting how many soaps and bath bombs they sell in a given day. In total, th
Vedmedyk [2.9K]

Answer:

33 = x + (3x + 1)

x = bath bombs

So 3x is three times as many bath bombs, then the plus one makes it so that the soaps sold is more than three times the amount of bath bombs sold

8 0
3 years ago
Which expression is equal to a + (b + c)?
stellarik [79]
A is the correct answer
7 0
3 years ago
Read 2 more answers
A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl
dusya [7]

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0
3 years ago
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