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VikaD [51]
3 years ago
10

Riggoletto’s Portraits specializes in making circular portraits of people. A large portrait is 78 in. in diameter. A medium port

rait is 26 in. in diameter. Estimate the difference between the areas of the two sizes of portraits. Use 3.14 for . Round your answer to the nearest whole number.
Mathematics
2 answers:
lawyer [7]3 years ago
8 0

Answer:

4245

I hope this answer helps!

Aleksandr-060686 [28]3 years ago
5 0

Answer:

heyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Step-by-step explanation:

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Svetlanka [38]

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A y=-2x-2 I think so sorry if wrong

8 0
3 years ago
What is the depth of the Indian Ocean rounded to the nearest thousand
gogolik [260]
Hey There!

The depth of the Indian Ocean rounded to the nearest thousand is 13,000.
7 0
3 years ago
Please help me with this
Fiesta28 [93]

9514 1404 393

Answer:

  91°

Step-by-step explanation:

The similarity statement tells you that angles Q and H are congruent. The measure of angle H is shown as 91°, so that is the measure of angle Q.

  m∠Q = 91°

5 0
3 years ago
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
4 years ago
Manuel has $600 in a savings account at the beginning of the summer. He wants to have at least $300 in the account at the end of
stiks02 [169]
The answer to this question is 600-28w > 300. This inequality can be described as $600 (money in the savings account) subtracted by $28w (withdrawal of $28 a week for food) should be greater than $300. It proves that the money will not drop below $300.
6 0
3 years ago
Read 2 more answers
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