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VashaNatasha [74]
3 years ago
11

It's 5 degrees outside and the temperature is expected to drop 4 degrees each hour for the next 3 hours. What will the temperatu

re be in 3 hours
Mathematics
1 answer:
klemol [59]3 years ago
8 0

I think it is - 5 I think

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During the 1920s, buying stock on credit was called buying on speculation. buying on a gamble. buying on margin. buying on margi
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Explanation: Buying on margin is borrowing money from a broker in order to purchase stock.

I hope this helps!!
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3 years ago
Read 2 more answers
6y^-4 using only positive exponents
Harlamova29_29 [7]
Y⁻¹ = \frac{1}{y^{4} }

y^{-4} =  \frac{1}{y^{4} }

6*\frac{1}{y^{4} }
= \frac{6}{y^{4} }
6 0
3 years ago
A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find
Lyrx [107]
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2 
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
4 0
4 years ago
17. Joan's Candy Emporium is having a sale. Three pounds of gummy bunnies are
Kazeer [188]

Answer:

$1.99 per pound

Step-by-step explanation:

5.97 / 3 = 1.99

5 0
3 years ago
Please answer these with lots of detail. I want to be able to understand the topic and material well.
IRISSAK [1]

Step-by-step explanation:

Q3

(a) If 0 < |x − 1| < δ, then |f(x) − 2| < 2

What this means is, how far can x stray from the x=1 line such that f(x) stays within 2 units of the y=2 line (0 < f(x) < 4).

If we move 2 units left of x=1, we get f(x) = 4.

If we move about 3.5 units right of x=1, we get f(x) = 4.

Therefore, δ can't be more than 2.

(b) If 0 < |x| < δ, then |f(x) − 3| < 1

What this means is, how far can x stray from the x=0 line such that f(x) stays within 1 unit of the y=3 line (2 < f(x) < 4).

If we move 1 unit left of x=0, we get f(x) = 4.

If we move 1 unts right of x=0, we get f(x) = 2.

Therefore, δ can't be more than 1.

Since f(x) isn't continuous within this domain, we can't conclude that the limit exists.

Q4

(a) Yes.  If δ = 0.25, then 0.75 < x < 1.25, and f(x) > 200.

(b) No.  f(1) = 300, so even if δ = 0, f(x) will be less than 400.

(c) Yes.  If δ ≈ 0.1, then 0.9 < x < 1, and f(x) > 450.

6 0
4 years ago
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