If x>4, then the quantity x-3 inside the absolute value symbol is already positive. So, in this case, |x-3| => x-3, and x-3 is all you need to write.
Answer:
a.(+4) and (+2)
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D. Donatello
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Answer:
3
Step-by-step explanation:
if you do the math 5+5 is 10 and 3.5 is half of 5 so the answer if you round is 3
Answer:
ax^3+3x^2-bx-6/x^2+3x+2 ( Please specify the equation if I'm wrong)
Step-by-step explanation:
ax^3+3x^2-x^2-bx-3x-6-2
=ax^3+2x^2-x(b+3)-8