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3 years ago

Volume of a cylinder with a diameter of 6 inches and a height that is three times the radius

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

8 0

Answer:

254.47 i think

Step-by-step explanation:

Elis [28]3 years ago

3 0

Answer: 254.47 cubic inches

Step-by-step explanation:

You are told that d = 6 so since the radius is half the diameter, r = 3. Use this to find h: h is 3 times the radius so h = 3 times 3 = 9. Now use the formula for the volume of a cylinder and plug in these values:

V = pi r^2 h

V = pi (3)^2 (9) = 81pi = 254.47 cubic inches

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Venita is factoring the expression 32ab-ab. She determines the GCF and writes the factored expression as 8b(4a-0) Which best des

Ymorist [56]

A) she incorrectly determined the GCF.

The GCF of 32ab - ab would be ab, not 8b.

7 0

2 years ago

Read 2 more answers

Si en 11 cajas de chocolates hay 220 chocolates en total. Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.

pochemuha

Answer:

Habrá 100 chocolates en total en 5 cajas de chocolates.

Step-by-step explanation:

Esta pregunta es resolvida usando proporciones, con lo uso de regla de tres .

11 cajas, 220 chocolates:

Entonces:

$\frac{220}{11} = 20$

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Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.

20 chocolates por caja, entonces:

5*20 = 100

Habrá 100 chocolates en total en 5 cajas de chocolates.

6 0

2 years ago

Which of the following numbers would have 10^3 in its scientific notation?

Monica [59]

Answer:

D. 9,700

Step-by-step explanation:

6 0

2 years ago

Question 20: Please help what are sin x and cos x?

sweet [91]

Answer:

A is the correct answer.

Step-by-step explanation:

$\tan x = \frac{6}{8} = \frac{opposite \: side \: to \: \angle \: x}{adjacent \: side \: to \: \angle \: x} \\ \\ hypotenuse \\ = \sqrt{ {(opp. \: side)}^{2} + {(adj. \: side)}^{2} } \\ = \sqrt{ {6}^{2} + {8}^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \\ = 10 \\ \\ \because \sin (x) = \frac{opposite \: side \: to \: \angle \: x}{hypotenuse} \\ \\ \huge{ \red{ \boxed{\therefore \: \sin (x) = \frac{6}{10}}}} \\ \\ \cos (x) = \frac{adjacent \: side \: to \: \angle \: x}{hypotenuse} \\ \\ \huge{ \purple{ \boxed{\therefore \: \cos (x) = \frac{8}{10} }}} \\$

Thus, option A is the correct answer.

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3 years ago

What is the range of the function y=\cos 2x ?

sattari [20]

All real numbers is the answer

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3 years ago