I like to divide by 2 first, and 347 divided by 2 is 173.5, so obviously this won't turn out evenly. I then divide 173.5 by 2, and that would be 86.75, so there's your answer!
Hope this helps!
Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that
95% confidence level
So , z is the value of Z that has a p-value of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Answer:
2x - 5
Step-by-step explanation:
1/5(10x - 25)
Use the Distrubitve Property
1/5 * 10x = 2x
1/5 * 25 = 5
New equation is 2x - 5
F(x) = 2x² + 7x - 5
g(x) = -8x² - 3x + 5
g(x) + f(x) = -8x² - 3x + 5 + 2x² + 7x - 5 = - 6x² + 4x
Answer: -6x² + 4x