<span>The driver’s foot must remain firmly on the brake pedal to activate the ABS.
An Anti-lock Brake system (ABS) is an effective braking system if used correctly. It simply keeps the foundation braking systems from locking up. It allows the driver to maintain directional stability and in some cases, reduces stopping distances during emergency situations when a driver slams the brake.
The foot of those drivers in vehicles equipped with ABS should remain firmly on the brake pedal, allowing this system to automatically kick in. In case of a slippery road or a panic stop, an Anti-lock Brake system prevents wheel lock up and helps your vehicle maintain a straight line</span>
Answer:
Following are the description of the given nodes:
Explanation:
The Multiple Access frequency - division facilitates control by granting every node a fixed time slot. Also, every slot seems to be identical in width. Its whole channel bandwidth is often used in every channel node. Compared to FDMA it takes more time.
Time slot=3 frames for all the above scenario
- In the first point, It is reserved the node 1, and as well as 3 frames were also transmitted 1.
- In the second point, It is reserved the node 2, and as well as 3 frames are transmitted.
- In the third point, It is reserved 3 nodes, and as well as 3 frames were transmitted.
- In the fourth point, It is reserved 4 slots and the transmit 3 frames.
- In the fifth point, It stores the slot 1 and the transmit 3 frames.
- In the sixth point, It stores the slot 2 and the transmit 1 frame.
- In the seventh point, It stores the slot 3 and the transmit 3 frames.
- In the Eight points, It stores the slot 3 and the transmit 2 frames.
Time interval = number of frames in first slot Time to send 1 frame number of images
Answer:
Kindly check the attachment.
Explanation:
We have the maximal count = 2^n - 2. Although, normally we can use 2^n = 2^3= 8( which means MOD-8 counter, but we need MOD-6). Therefore, the maximum count should be 6 - 1 Which is equal to 5. The total number of states is 6, then with these we can define our MOD-6
So, using;
Values of Qc, Qb, Qa and their respective Decimal equivalent are given below;
0 0 0 0
0. 0 1 1
0 1 0 2
0 1 1 3
1 0 0 4
1 0 1 5
1 1 0 6*(reset).
Thus, 0 - 5 => MOD-6 counting.
Check the attachment for the logical diagram
After the simulation, run the circuit to test if it is working efficiently.
Answer and Explanation:
if all your program works fine, without any compilation error, then open command prompt and navigate to the folder "cs252/Assignments/guess" where you have all the header and c++ files stored.
type to generate "program" executable file :- g++ -o program guess.cpp
To execute the so obtained executable:- ./program