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const2013 [10]
3 years ago
12

Which two technologies support the building of single-page applications? and are two technologies helpful in building single pag

e applications.\
Computers and Technology
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

You can use JavaScript, HTML, PHP and so forth.

Explanation:

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<span>Budget for fixed expenses before flexible expenses.</span>
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I need help!!! i will make you a brainliest!!
Ber [7]

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What you have is correct

Explanation:

3 0
3 years ago
Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any
vampirchik [111]

Answer:

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>  

int n; //to store size of array  

char* ArrayChallenge(int arr[]) //function returns string true or false

{

  int i, j;

  int sum = 0;

  for(i = 0; i < n; i++)

  {

      sum = sum + arr[i]; //count sum

  }  

  for(i = 0; i < n; i++)

  {

      for(j = i+1; j < n; j++) //loop for every two elements in array

      {

          if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

          {

              printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

              return "true"; //If proudct of two elements > 2 times sum. return true

          }

      }

  }

  return "false"; // If proudct of two elements < 2 times sum. return false

}  

int main()

{  

  printf("\nEnter size of array: ");

  scanf("%d", &n); //read size of array

  int A[n]; //array of size n

  printf("\nEnter array elements: ");

  int i;

  for(i = 0; i < n; i++)

  {

      scanf("%d", &A[i]); //read array from stdin

  }

  printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

 

  return 0;

}

6 0
3 years ago
You’ve just installed a software update, rebooted, and now your system experiences random crashes. Which too in Windows 8.1 enab
Usimov [2.4K]

Answer:

Action Center

Explanation:

The Action Center is a feature in window 8.1 that monitors security and maintenance on your computer.It notifies you when there is an issue.Through this user can view alerts and updates about software support problem.

5 0
4 years ago
Write a SELECT statement that returns one row for each customer that has orders with these columns:
d1i1m1o1n [39]

Answer:

SELECT email_address,

SUM(item_price * Quantity) AS item_price_total,

SUM(discount_amount * Quantity) AS discount_amount_total

FROM Customers c

JOIN Orders o ON c.CustomerID = o.CustomerID

JOIN Order_Items oi ON o.OrderID = oi.OrderID

GROUP BY email_address

ORDER BY item_price_total DESC

Explanation:

In this SQL statement the SELECT statement selects the following columns:

email_address

item_price

Quantity

discount_amount

There are two tables Customers and Order_Items

SUM aggregate function is used to add the values of the product of the columns discount_amount and Quantity. It is also used to get the sum of the product of two columns discount_amount and Quantity.

A new temporary column named item_price_total is used to name the sum of the product of two columns discount_amount and Quantity using AS which is ALIAS and it is used to give a name to some columns or a table.

Similarly discount_amount_total name is given to the column which calculate the sum of the product of two columns i.e. discount_amount and Quantity.

JOIN is used here to join the columns from the tables Order_items and Customers.

GROUP BY is used to group the result of rows and is used with functions like SUM. Here the rows are grouped by the email address.

ORDER BY is used to order the result. Here the result is ordered by item_price_total in descending  order.

This SELECT statement can also be written as following:

SELECT c.email_address,

SUM(o.item_price * o.Quantity),

SUM(o.discount_amount * o.quantity)

FROM customer c

JOIN Order_Items o ON o.id = c.id

GROUP BY c.email_address

7 0
4 years ago
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