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Serga [27]
3 years ago
14

Help me please I need an an answer asap

Mathematics
1 answer:
Dovator [93]3 years ago
8 0
7B + 4 = 7B - 3
We need to solve for B
Let's add 3 in both sides:

7B + 4 = 7B - 3
7B + 4 + 3 = 7B - 3 + 3
7B + 7 = 7B

Let's subtract 7B from both sides:
7B + 7 = 7B
7B - 7B + 7 = 7B - 7B
7 = 0

7 = 0, which is impossible. 7 can never be 0, and 0 can never be 7.
So the equation have no solution.
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Giving 10 points to anyone who answers these
sineoko [7]
I'm not sure about the first question.
Did you post the question correctly?

7 0
3 years ago
F is a polynomial of degree 6. f has a root of multiplicity
frutty [35]

Answer:

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

Step-by-step explanation:

We have a 6th degree polynomial  f(x)

r = 3 is a root of f with multiplicity 2

r = 1 is a root of f with multiplicity 3

f(-5) = -29721.6

f(-10) = 0

Then:  f(x) = a*((x -3)^2 ) * ((x - 1)^3)*(x + 10)

f(-5) = a *  (-8)^2 *  (-6)^3  *  (5)  =  -29,721.6

a* (64) * (-216)* 5 = -29,721.6

-a*69,120 = -29,721.6

a =  -29,721.6/-69,120

a =  0.43

so

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

4 0
3 years ago
4X + 5Y = 21<br> -4X + 8Y = -8<br> And<br> X + 5Y = 5<br> 3X - 5Y = 3
sergij07 [2.7K]

Answer:

for the first one

Step-by-step explanation:

(x,y)=(4,1)

6 0
3 years ago
Let f be defined as shown. If the domain is
vitfil [10]

Answer:

Inverse of F does not exist

Step-by-step explanation:

2 different x values lead to 1 y value therefore it cannot be reversed

8 0
3 years ago
If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
Anna007 [38]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0
3 years ago
Read 2 more answers
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