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Leviafan [203]
4 years ago
14

Which number is a factor of 12, but not a multiple of 6?

Mathematics
2 answers:
BlackZzzverrR [31]4 years ago
6 0
4
4*3 is 12 but 4 is not a multiple of 6 

mafiozo [28]4 years ago
6 0
To solve this, list all the known integer factors of 12:
3 and 4, 2 and 6, 1 and 12.
Now, look at each factor (1, 2, 3, 4, 6, 12) and list a couple of the multiples of 6 which include: 6, 12, 18, 24, 30, etc.
When you look back at the factors you notice that 1,2,3, and 4 are not a multiple of 6, therefore 1,2,3, and 4 are the numbers which is a factor of 12 and not a multiple of 6. 
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Andy carried 1/2 gallon of water on a hike. He drank 2/3 of the water. How much water did he drink?
GarryVolchara [31]
Water carried = 1/2 gallon

Water drank =
= 2/3 of 1/2 gallon
= 2/3 × 1/2
= 2/6
= 1/3 gallon
5 0
3 years ago
Find the mean of the data in the dot plot below.
ladessa [460]

Answer:

The answer would be, 2.75

Step-by-step explanation:

Add all the numbers up:

0+1+1+2+3+4+5+6=22

Divide the answer by the amount of numbers:

22÷8=2.75

4 0
3 years ago
Read 2 more answers
How to get 2 essays and pre-essay questions done in 238 minutes? (3 hours and 58 min) PLEASE HELP
Amanda [17]

Answer:

Definitely start with outlining one essay, then doing all of your steps, although don't do much re-writing since there may not be enough time. only focus on one at a time though. as for the questions, since it says pre-essay it wants that completed first but unless you have to do it first, i would do it last since the essays are more important.

8 0
3 years ago
Read 2 more answers
Find the area of Rhombus if its diagonals measure 18 cm and 21 cm​
Dennis_Churaev [7]

Answer:

189 cm²

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = \frac{1}{2} × product of diagonals

   = \frac{1}{2} × 18 × 21 = 9 × 21 = 189 cm²

3 0
3 years ago
Binomial ( 5x - y ) ^ 10 terms ax ^ 2 y ^8
iragen [17]
\bf (5x-y)^{10}\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&+1&(5x)^{10}(-y)^0\\
2&+10&(5x)^9(-y)^1\\
3&+45&(5x)^8(-y)^2\\
4&+120&(5x)^7(-y)^3\\
5&+210&(5x)^6(-y)^4\\
6&+252&(5x)^5(-y)^5\\
7&+210&(5x)^4(-y)^6\\
8&+120&(5x)^3(-y)^7\\ 9&+45&(5x)^2(-y)^8
\end{array}

now, how do we get the coefficients?  well, the first coefficient is 1, any subsequent is " the product of the current terms's coefficient and the exponent of the first element, divided by the exponent of the second element in the next term", now that's a mouthful, but for example,

how did get 210 for the 5th expanded term?  well is just 120 * 7 / 4

how about 252 of the 6th term?   210 * 6 / 5.

how about 45 of the 9th one?  120 * 3 / 8.

of course, the exponents for each is simple, as you'd already know from the binomial theorem.

so, just expand away the 9th expanded term.
3 0
3 years ago
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