Answer: 29
explanation: you add 1 to get 2, you then add 2 to get 4, then 3 to get to 7, then 4 to get to 11, then 5 to get to 16, then 6 to get to 22, then 7 to get to 29
Answer:
44
Step-by-step explanation:
1. (3+14)=17
2. 17 + 27= 44
Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
The answer is 140
140 x 0.1 (10% as a decimal) = 14