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jarptica [38.1K]
3 years ago
11

We have seen that the standard deviation σ measures the spread of a data set about the mean μ. Chebyshev’s inequality gives an e

stimate of how well the standard deviation measures that spread. One consequence of this inequality is that for every data set at least 75% of the data points lie within two standard deviations of the mean, that is, between μ−2σ and μ+2σ (inclusive). For example, if μ = 20 and σ = 5, then at least 75% of the data are at least 20−2×5 = 10 and at most 20+2×5 = 30. Our statement of this result says at least 75%, not exactly 75%. Consider the following data: 5, 10, 10, 10, 10, 10, 10, 15. The percentage of data points that actually lie within two standard deviation of the mean is ______%
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

100

Step-by-step explanation:

First we find the mean of this set of data.  We find the mean by finding the sum of data values and dividing it by the number of data values:

5+10+10+10+10+10+10+15 = 80

There are 8 data values; 80/8 = 10.  The mean is 10.

To find the standard deviation, subtract the mean from each value; square the difference; add the squares; divide by the number of data values; and take the square root:

5-10 = -5; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 15-10 = 5

(-5)^2 = 25; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 5^2 = 25

25+0+0+0+0+0+0+25 = 50

50/8 = 6.25

√6.25 = 2.5

The standard deviation is 2.5.

This means two standard deviations, or 2σ, is 2(2.5) = 5.

This gives us μ-2σ = 10-5 = 5 and μ+2σ = 10+5 = 15.

Since all of our data is between 5 and 15, 100% is within two standard deviations of the mean.

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As a freshman, suppose you had to take two of four lab science courses, one of two literature courses, two of three math courses
Sergeeva-Olga [200]

Answer:

We have 252 different schedules.

Step-by-step explanation:

We know that as  a freshman, suppose you had to take two of four lab science courses, one of two literature courses, two of three math courses, and one of seven physical education courses.

So from 4 lab science courses we choose 2:

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C_1^2=\frac{2!}{1!(2-1)!}=2

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C_2^3=\frac{3!}{2!(3-2)!}=3\\

So from 7 physical education courses we choose 1:

C_1^7=\frac{7!}{1!(7-1)!}=7

We get: 6 · 2 · 3 · 7 = 252

We have 252 different schedules.

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3 years ago
The base of my triangle is 2.5 meters. The area is 3.75 square meters. What is the height?
AysviL [449]
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4 years ago
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nirvana33 [79]
I think it would be 26. I hope that helped.
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4 years ago
12(43)
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