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jarptica [38.1K]
3 years ago
11

We have seen that the standard deviation σ measures the spread of a data set about the mean μ. Chebyshev’s inequality gives an e

stimate of how well the standard deviation measures that spread. One consequence of this inequality is that for every data set at least 75% of the data points lie within two standard deviations of the mean, that is, between μ−2σ and μ+2σ (inclusive). For example, if μ = 20 and σ = 5, then at least 75% of the data are at least 20−2×5 = 10 and at most 20+2×5 = 30. Our statement of this result says at least 75%, not exactly 75%. Consider the following data: 5, 10, 10, 10, 10, 10, 10, 15. The percentage of data points that actually lie within two standard deviation of the mean is ______%
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

100

Step-by-step explanation:

First we find the mean of this set of data.  We find the mean by finding the sum of data values and dividing it by the number of data values:

5+10+10+10+10+10+10+15 = 80

There are 8 data values; 80/8 = 10.  The mean is 10.

To find the standard deviation, subtract the mean from each value; square the difference; add the squares; divide by the number of data values; and take the square root:

5-10 = -5; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 10-10 = 0; 15-10 = 5

(-5)^2 = 25; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 0^2 = 0; 5^2 = 25

25+0+0+0+0+0+0+25 = 50

50/8 = 6.25

√6.25 = 2.5

The standard deviation is 2.5.

This means two standard deviations, or 2σ, is 2(2.5) = 5.

This gives us μ-2σ = 10-5 = 5 and μ+2σ = 10+5 = 15.

Since all of our data is between 5 and 15, 100% is within two standard deviations of the mean.

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Answer:

Question 21: -6-(-3)

Question 22: -7+12

4 0
3 years ago
Read 2 more answers
There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
4 years ago
the cost of fencing a rectangular field at rupees 30 per metre is rupees 2400 if the length of the its field is 24m than its bre
prohojiy [21]

Answer:

breadth = 8, length = 32

Step-by-step explanation:

perimeter = 2 x (length x breadth)

                = 2 x ((24 + b) + b))

                = 2 x (24 + 2b)

                = 48 + 4 b

48 + 4b meters costs rupees 2400

each meter costs rupees 30

so,

30 x (48 + 4b) = 2400

1440 + 120b    = 2400

           120b    = 960

                 b    = 8

the breadth is 8m, the length is 8 + 24 = 32m

3 0
3 years ago
The mean income per person in the United States is $44,500, and the distribution of incomes follows a normal distribution. A ran
Artist 52 [7]

Answer:

We conclude that the residents of Wilmington, Delaware, have higher income than the national average

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = $44,500

Sample mean, \bar{x} = $52,500

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, s =  $9,500

a) First, we design the null and the alternate hypothesis

H_{0}: \mu = 44,500\text{ dollars}\\H_A: \mu > 44,500\text{ dollars}

We use one-tailed(right) t test to perform this hypothesis.

c) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{52500 - 44500}{\frac{9500}{\sqrt{16}} } = 3.37

b) Rejection rule

If the calculated t-statistic is greater than the t-critical value, we fail to accept the null hypothesis and reject it.

Now,

t_{critical} \text{ at 0.05 level of significance, 15 degree of freedom } = 1.753

Since,                    

t_{stat} > t_{critical}

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis. We conclude that the residents of Wilmington, Delaware, have higher income  than the national average

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3 years ago
1. Determine whether the regular hexagon has reflection symmetry, rotation symmetry, both, or neither. If it has reflection symm
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The regular hexagon has both reflection symmetry and rotation symmetry.

Reflection symmetry is present when a figure has one or more lines of symmetry. A regular hexagon has 6 lines of symmetry. It has a 6-fold rotation axis.

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Rotation symmetry is present when a figure can be rotated (less than 360°) and still look the same as before it was rotated. The center of rotation is a point a figure is rotated around such that the rotation symmetry holds. A regular hexagon can be rotated 6 times at an angle of 60°

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3 0
4 years ago
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