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kumpel [21]
3 years ago
13

How to solve 8(3p-1)+9=3(p+2)-1 ?

Mathematics
1 answer:
kari74 [83]3 years ago
7 0

Answer:

4/21

Step-by-step explanation:

1. distribute

24p-8+9=3p+6-1

2. combine like terms on each side

24p+1=3p+5

3. solve for p

21p=4

p=4/21

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anygoal [31]
-1. hope that helps!
3 0
3 years ago
Katy is on a path, moving towards a bridge. The given table represents a function that describes Katy’s distance from the bridge
Sophie [7]

Answer:

D : Katy was 300 meters from the bridge, and it took her 6 minutes to reach the bridge.

Step-by-step explanation:

Recall that x represents the time walked

When you see the first entry on the table as: x=0, that means Katy is about to start her walk, and the value to the right which represents her distance from the bridge is 300 meters. So as her walk started she was 300 meters from the bridge.

Now look at the last entry pair at the bottom of the table: the value in the "x" column (that represents the number of minutes she walked) reads: 6, and the value to the right (next column) reads 0 (0 meters from the bridge)

This is telling us that Katy was at the bridge after 6 minutes of walk. So answer D is the correct answer representing the given table of time and distance values.

3 0
3 years ago
Adam sleeps for nine hours each night, five nights a week, and 11 hours for two nights a week.
melisa1 [442]

Answer:

E

Step-by-step explanation:

3 0
3 years ago
What is the number 5 2/7 written as a improper fraction
WARRIOR [948]

Answer:

the answer is 37/7

Step-by-step explanation:

u multiply the 5 and the seven and add the 2 and u get 37/7 so u keep the denominator the same

5 0
3 years ago
69) Half-way to the center of a planet of uniform density, your weight compared to that at the surface would be :
mel-nik [20]

Answer:

One- half

Step-by-step explanation:

Since the density is uniform  

Mass of the sphere = [(4/3) π r^3] d

where d is the uniform density.

Mass of the sphere = [(4/3) π d] r^3 = k r^3

where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

7 0
3 years ago
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