Answer/Step-by-step explanation:
Part A: Net A is the correct net. If we decide to fold the net, we'd get the shape of the prism. Folding back net B won't give us the shape of the prism because of the position and arrangement of the right triangular bases.
Part B:
AB = 3in
BC = 5 in
CD = 9.4 in
Part C: surface area of the prism can be calculated by calculating the area of each part of the net, and summing them together as follows,
Area of the 2 triangular bases = 2(½*base*height of triangle) = 2(½*4*3) = 2*2*3 = 12 in²
Area of the three rectangles =

Surface area of prism = 12 + 112.8 = 124.8 in²
A proportional relationship is a relationship between variables such that the amount of one variable is a multiple of the other variable
A table showing the amount of sugar in different sizes of orange juice is presented as follows;
![\begin{array}{|c|cc|}\mathbf{Amount \ of \ orange \ juice, \ x}&&\mathbf{Quantity \ of \, sugar\ (g), \ f(x)}\\3&&8.25\\6&&16.5\\9&&24.75\\12&&33\\15&&41.25\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Ccc%7C%7D%5Cmathbf%7BAmount%20%5C%20of%20%5C%20orange%20%5C%20juice%2C%20%5C%20x%7D%26%26%5Cmathbf%7BQuantity%20%5C%20of%20%5C%2C%20sugar%5C%20%28g%29%2C%20%5C%20f%28x%29%7D%5C%5C3%26%268.25%5C%5C6%26%2616.5%5C%5C9%26%2624.75%5C%5C12%26%2633%5C%5C15%26%2641.25%5Cend%7Barray%7D%5Cright%5D)
Reason:
The given parameter are;
12 ounces of orange juice contains 33 grams of sugar
Therefore, we have;
The amount of sugar per ounce of orange juice is given as follows;

Therefore, there are 2.75 grams of sugar per ounce of orange juice
which gives;
The amount of sugar in different sizes of orange juice, f(x) = 2.75·x
Where <em>x</em> represents the amount of orange juice, and f(x) represents the amount of sugar in the orange juice
A table showing the amount of sugar present in different sizes of orange juice is given as follows;
![\begin{array}{|c|cc|}\mathbf{Amount \ of \ orange \ juice, \ x}&&\mathbf{Quantity \ of \, sugar\ (g), \ f(x)}\\3&&8.25\\6&&16.5\\9&&24.75\\12&&33\\15&&41.25\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Ccc%7C%7D%5Cmathbf%7BAmount%20%5C%20of%20%5C%20orange%20%5C%20juice%2C%20%5C%20x%7D%26%26%5Cmathbf%7BQuantity%20%5C%20of%20%5C%2C%20sugar%5C%20%28g%29%2C%20%5C%20f%28x%29%7D%5C%5C3%26%268.25%5C%5C6%26%2616.5%5C%5C9%26%2624.75%5C%5C12%26%2633%5C%5C15%26%2641.25%5Cend%7Barray%7D%5Cright%5D)
Learn more here:
brainly.com/question/18424356
brainly.com/question/12725505
<em><u>Complete Question:</u></em>
You can model the population of a certain city between 1955-2000 by the radical function
P(x) = 55,000 sqrt x-1945
Using this model, in which year was the population of that city 275,000?
<em><u>Answer:</u></em>
In 1970 population of that city is 275,000
<em><u>Solution:</u></em>
Given that,
<em><u>You can model the population of a certain city between 1955-2000 by the radical function
:</u></em>

To find: year in which was the population of that city 275,000
Therefore,
x = ?
P(x) = 275000
Thus we get,

Thus, in 1970 population of that city is 275,000
the numerators are the top number and the numbers are: 11, 7, 12, and 0
the denominator is the bottom and the numbers are: 12, 512, 10, and 78
hope this helps!