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1 answer:

8 0

A real world example is when a patient is injected with medicine until the concentration of the medicine in the blood is at its ideal level. Here is how you would graph it. In a table it would be on the left side, 123456, and on the right side, 1, 0.5, 0.25, 0.2, 0.15, 0.1

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-2x - y = -9 5x -2y = 18 Solve as a whole number

nexus9112 [7]

Answer:

x = 4, y = 1

(4, 1)

Step-by-step explanation:

-2x - y = -9

5x -2y = 18

-2x - y = -9

+2x +2x

-y = 2x - 9

/-1 /-1

y = -2x + 9

5x -2y = 18

5x - 2(-2x + 9) = 18

5x + 4x - 18 = 18

9x - 18 = 18

+ 18 + 18

9x = 36

/9 /9

x = 4

Now, we solve for y:

-2(4) - y = -9

-8 - y = -9

+ 8 +8

-y = -1

/-1 /-1

y = 1

(x, y) -> (4, 1)

Hope this helps!

6 0

3 years ago

Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit

Anestetic [448]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let $\hat p$ = the sample proportion of defectives.

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P( $\hat p$ > 0.13)

P( $\hat p$ > 0.13) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ > $\frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}} }$ ) = P(Z > -2.74) = P(Z < 2.74)