Question

Write using algebra.

Answer 1

Answer:

a bucket can hold $\frac{c}{c-8}$ times water in a jug.

Step-by-step explanation:

A bucket holds the water = c liters

A jar holds 8 liters less water than a bucket

= (c - 8) liters

Therefore, $\frac{\text{Water in the bucket}}{\text{Water in a jug}}=\frac{c}{c-8}$

Water in the bucket = $\frac{c}{c-8}\times {\text{Water in a jug}}$

Therefore, a bucket can hold $\frac{c}{c-8}$ times water in a jug.

Answer 2

Y=c litters
y-8= x
x=amount of water in the jar
x-y=