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marta [7]
3 years ago
7

I will give you brainiest if you can answer the questions below.

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

a. i. 3000 cm² ii. 220 cm  b.  6 feet

Step-by-step explanation:

A. i. The area of the sector AOB is A = ¹/₂r²θ where r = radius of circle = 50 cm and θ = angle subtended at the center of the circle by the sector in radians = 2.4 radians.

So, A = ¹/₂r²θ

= ¹/₂(50 cm)² × 2.4 rad

= ¹/₂ × 2500 cm² × 2.4 rad

= 1250 cm² × 2.4 rad

= 3000 cm²

ii. The perimeter of the sector is P = 2r + rθ = (2 + θ)r

substituting r and θ, we have

P = (2 + θ)r

= (2 + 2.4) × 50 cm

= 4.4 × 50 cm

= 220 cm

B. Since length of an arc L = rθ where r = radius = length of pendulum and θ = angle swept by pendulum =  ½ radian and length of the arc swept = 3 feet, the radius is

r = L/θ

= 3 feet ÷ ½ rad

= 3 × 2

= 6 feet

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alexdok [17]

Answer:

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Step-by-step explanation:

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Pls mark me as brainliest!!!!

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2 inches is equal to 300 miles if you drive 450 miles how many inches does it represent on the map​
Lunna [17]

Answer:

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Step-by-step explanation:

7 0
3 years ago
A pilot flies on a bearing of 160° for 30 miles. The pilot then executes a quick turn and flies another 15 miles at a bearing of
vivado [14]

Answer: 34.65 miles at an angle of 325.39°

Step-by-step explanation:

Ok, the initial position is (0,0)

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p = (30*cos(120°), 30*sin(120°))

Then she travels another 15 miles at an angle of 205°, the new position is:

p = (30*cos(120°) + 15*cos(205°), 30*sin(120°) + 15*sin(205°))

p = (-28.59 , 19.64)

If she now travles X miles at an angle Y, we must have that the final position is the point (0,0)

this means that:

X*cos(Y) = -(-28.59) = 28.59

X*sin(Y) = -19.64

Now, we can find the quotient between those two equations and use that tan(x) = sin(x)/cos(x)

X*(sin(Y))/(X*cos(Y)) = -19.64/28.59

Tg(Y) = -0.69

Y = ATg(-0.69) = -34.61°

If we use only positive angles, this angle is equivalent to:

360° - 34.61° = 325.39°

now lets find the distance:

Xcos(325.39°) = 28.59

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4 0
3 years ago
You are designing a ramp where the horizontal distance is twice the vertical rise. what will be the ramp angle to the nearest te
ankoles [38]
Use the definition of tangent

or inv tangent (arctan or atan)

tan(theta) = opposite side/ adjacent side

the vertical rise would be the opposite side, the horozontal distance would be the adjacent side

let rise = y
let distance= x
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so tan(theta) = y/2y
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grab a handy dandy calculator, unless you know this conversion off the top of your head
7 0
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