Answer:
x=21° and ∠KMH=96°
Step-by-step explanation:
From the given information that a bike path crosses a road and the given figure, we get
∠GMH=∠KMI=84°(Vertically opposite angles)
⇒4x=84°
⇒x=21°
therefore, the value of ∠GMH=4x=4(21)=84°
Now, ∠KMH+∠KMI=180°( Linear pair)
⇒∠KMH+84°=180°
⇒∠KMH=180-84
⇒∠KMH=96°
Thus, the value of ∠KMH is 96°
Answer:
- 2 x y^2+3 x^2 y -xy
-120
Step-by-step explanation:
xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2
Combine like terms
xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2
- x y+3 x^2 y - 2 x y^2
Let x = 4 y = -2
-(4)(-2) +3(4)^2 (-2) -2(4)(-2)^2
Exponents first
-(4)(-2) +3(16) (-2) -2(4)(4)
Multiply
+8 -96-32
Add and subtract
-120
<span><span>(80.08)</span><span>(2.02) </span></span>=161.7616 ; (72.8)(2.5)= 182
Answer:
60⁰ hope I'm right
Step-by-step explanation:
I think