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Otrada [13]
3 years ago
6

Michael is packing books into boxes. Each box can hold either 15 small books or

Mathematics
1 answer:
zavuch27 [327]3 years ago
7 0

Let x equal the number of tiny book boxes and y equal the number of large book boxes.

Because John must pack at least 35 boxes:

(number of tiny book boxes) + (number of large book boxes) = (at least) 35

x + y ≥ 35

 

Since John needs to pack at least 350 books:

 

(number of small books packed) + (number of large books packed) (is at least) 350

(number of small books per box)(number of boxes of small books) + (number of large books per box)(number of boxes of small books) ≥ 350

15x + 8y ≥ 350

 

Your system of inequalities is:

 

x + y ≥ 35

15x + 8y ≥ 350

<h2>GO INTO DESMOS TO GRAPH</h2>
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Determina si 2018 es un termino de la siguiente progresion aritmetica 17,46,75,104,133,....
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2018 is the 70th term of the progression.

Explanation
We start out finding the common difference of the progression:
46-17 = 29

Now we write the explicit formula for the sequence.  It is of the form
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We set this equal to 2018 to see if the answer is a whole number.  If it is, it will be the term number that gives us 2018:

2018=17+29(n-1)

Using the distributive property,
2018=17+29*n-29*1
2018=17+29n-29

Combine like terms:
2018=29n-12

Add 12 to both sides:
2018+12=29n-12+12
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Divide both sides by 29:
2030/29=29n/29
70=n

Since n=70, this means 2018 is the 70th term of the sequence.
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3 years ago
A cube has a surface area of 294 square cm. Find the length of one side.
DerKrebs [107]
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6 0
3 years ago
How many atoms are in 882 moles of Li?
kogti [31]

Answer:

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Which three ordered pairs complete the table to give solutions of the equation y = –6x?
Anika [276]
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6 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
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