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salantis [7]
2 years ago
9

A random sample of students were asked which award they would most like to win (Olympic Gold, Academy Award, or Nobel Prize), an

d asked which portion of the SAT they performed better on, between the Math and the Verbal. The results are summarized in the table below. Use this table to answer the following question.
1. If P(M) is the proportion of students who did better on the Math portion of the SAT who prefer winning an Olympic Gold, and P(V) is the proportion of students who did better on the Verbal portion of the SAT who prefer winning an Olympic Gold. What is the standard error of the distribution of the difference of proportions?

Mathematics
1 answer:
Komok [63]2 years ago
3 0

Answer:

Well would of them just ask how and when they will get it?

Step-by-step explanation:

So sorry if this is wrong.

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garik1379 [7]
Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
\\\\\\
\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}

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Answer:

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Step-by-step explanation:

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