Answer:
For plastic
Year 1 97,000 units per year and 2 operators
Year 2 115,000 units per year and 3 operators
Year 3 136000 units per year and 3 operators
Year 4 141000 units per year and 3 operators
For bronze
Year 1 21000 units per year, 2 machines and 4 operators in total
Year 2 24000 units per year, 2 machines and 4 operators in total
Year 3 29000 units per year, 3 machines, 5 operators in total
Year 4 34000 units per year, 3 machines, 6 operators in total
Explanation:
for plastic,
since there is only one machine that is operated by 4 operators,
Units per operator= Machine speed/number of operator
= 200,000/4
= 50,000 units per operator
so for year 1, for 97,000 units 2 operators will be enough and for year 2, year 3 and year 4, 3 operators will be enough
for Bronze
since there are 3 machines and total number of 6 operators,
Units per operator= sum of speed of all machines/total number of operator
= 36000/6
= 6,000 units per operator
so for year 1 for 21,000 units per year, 4 operators will be required (6000×4) with 2 machines
for year 2 for 24000 units per year, 4 operators will be requried with 2 machines
for year 3 for 29,000 units per year, 3 machines will be required with 5 operators to meet the demand
for year 4 for 34,000 units, 3 machines will be requried with 6 operators
