Option A: z + 1
Option B: 6 + w
Option D: 
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
<u>To find which expressions are polynomial:</u>
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C: ![y^{2}-\sqrt[3]{y}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4)
![y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4%3Dy%5E%7B2%7D-%7By%7D%5E%7B1%2F3%7D%2B4)
Here, y have fractional exponent.
So, it is not a polynomial.
Option D:
By the definition, is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and are polynomials.
Answer:
The directrix is y=6 and focus is (0,4)
The equation of the parabola is,
20-4y=x²
The answer is (9x^8y^3)/2.
You start with the top number of each fraction and multiply them. So 2x3=6. Next you take the bottom number and multiply. So 3x4=12. That would give you a fraction of 6/12. 6 is half of 12 so 6/12 simplified is equal to 1/2. Hope this helps!
Answer:
The next number is 1321232112
Step-by-step explanation:
32 is read off as "one 3, one 2" = 1312
1312 is read off as "one 1, one 3, one 1, one 2" = 11131112
11131112 is read off as "three 1s, one 3, three 1s, one 2" = 31133112
31133112 is read off as "one 3, two 1s, two 3s, two 1s, one 2" = 1321232112
