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2 years ago

Which is another way of correctly expressing (x - 3)(x - 3)?

Mathematics

2 answers:

Pavlova-9 [17]2 years ago

8 0

Answer:

There are two ways.

1.) The box method

2.) F.o.i.l

Both of these are easy to do, but if you have trouble visualizing things in your head I suggest the box method.

Here is how I did the problem with the box method

worty [1.4K]2 years ago

5 0

(x-3)^2, as x-3 is repeated twice

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What is 2 + 5 - 2 x 9 = ? The person who gets it right, I will make you brainliest.

Minchanka [31]

PEMDAS
Multiplication: 2 + 5 - 18=
Addition: 7-18=
Subtraction: -11
Answer=-11

5 0

2 years ago

Read 2 more answers

Mike and Beth both write the decimal 0.8 (0.88888...)as a fraction. Mike: 45 Beth: 89 Which student wrote the correct fraction?

fenix001 [56]

Answer:

see the explanation

Step-by-step explanation:

we have

0.888...

This is a <u>repeating decimal</u> (Is a decimal that has a digit, or a block of digits, that repeat over and over and over again without ever ending)

Convert to fraction number

Let

x=0.888...

10x=8.888...

Subtract 0.888... from 8.888... to remove the decimal

10x-x=8.888...-0.888...

9x=8

Solve for x

x=8/9

therefore

Mike fraction is incorrect

because 4/5=0.8

0.8 is a <u>terminating decimal </u>(It's a decimal with a finite number of digits)

Mike's mistake was considering the number as a terminating decimal instead of a repeating decimal

Beth is correct

because

If you divide 8/9

the result is 0.8888888...

3 0

2 years ago

A firm has the marginal-demand function where D(x)=-1400x÷√25-x² is the number of units sold at x dollars per unit. Find the dem

borishaifa [10]

The equation of the demand function is D(x) = 1400√(25-x²) + 11400

<h3>How to determine the demand function?</h3>

From the question, we have the following parameters that can be used in our computation:

Marginal demand function, D'(x) = -1400x÷√25-x²

Also, we have

D = 17000, when the value of x = 3

To start with, we need to integrate the marginal demand function, D'(x)

So, we have the following representation

D(x) = 1400√(25-x²) + C

Recall that

D = 17000 at x = 3

So, we have

17000 = 1400√(25-3²) + C

Evaluate

17000 = 5600 + C

Solve for C

C = 17000 - 5600

So, we have

C = 11400

Substitute C = 11400 in D(x) = 1400√(25-x²) + C

D(x) = 1400√(25-x²) + 11400

Hence, the function is D(x) = 1400√(25-x²) + 11400