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Zolol [24]
3 years ago
11

Which is another way of correctly expressing (x - 3)(x - 3)?

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer:

There are two ways.

1.) The box method

2.) F.o.i.l

Both of these are easy to do, but if you have trouble visualizing things in your head I suggest the box method.

Here is how I did the problem with the box method

worty [1.4K]3 years ago
5 0
(x-3)^2, as x-3 is repeated twice
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A bag contains four red marbles, two green ones, one lavender one, three yellows, and one orange marble. HINT (See Example 7.] H
Murljashka [212]

Answer:  35

Step-by-step explanation:

Given : A bag contains four red marbles, two green ones, one lavender one, three yellows, and one orange marble.

Total = 4+2+1+3+1=11

To find sets of four marbles include none of the red ones, we need to exclude red marbles when we count the total number of marbles.

Then, the total marbles(exclude red) =11-4=7

Now, the combination of 7 marbles taking 4 at a time is given by :-

^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!3!}=35

Hence, the number of sets of four marbles include none of the red ones = 35

4 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
a trapezoid has base lengths of (6x-1) units and 3 units. Its midsegment has a length of (5x-3) units. What is the value of x?
vodka [1.7K]
1. You have that:

 - The<span> lengths of the bases are (6x-1) units and 3 units.
 - The midsegment has a length of (5x-3) units.

 2. To solve this exercise, you must apply the formula for calculate the length of the midsegment of a trapezoid, which is shown below:

 Midsegment=Base1+Base2/2

 As you can see, the midsegment is half the sum of the bases of the trapezoid.

 3. When you substitute the values, you obtain:

 (5x-3)=[(6x-1)+3]/2

 4. Now, you can solve the problem by clearing the "x":
</span>
 (5x-3)=[(6x-1)+3]/2
 2(5x-3)=6x-1+3
 10x-6=6x+2
 10x-6x=2+6
 4x=8
 x=8/4
 x=2
3 0
3 years ago
You are building a new wooden deck on your house. The old deck had a length of (2x + 1) feet and a width of (3x – 3) feet. You w
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Answer:

suggestions algebra calculator or math

5 0
3 years ago
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Only square matrices have multiplicative identities. True or false
Alex

Answer:

true.

Step-by-step explanation:

8 0
3 years ago
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