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PilotLPTM [1.2K]
3 years ago
10

Andy has a collection of movie DVD's. In Andy's collection 3/5 of the DVD's are action and 1/4 of the DVD's are comedy . Andy sa

id 4/9 of his collection is action is action or comedy . Cindy said that Andy made an error. Explain whether or not Andy is correct or incorrect and why.
Mathematics
2 answers:
valkas [14]3 years ago
8 0
Andy is wrong.
3/5 = 12/20
1/4 = 5/20
Add them up
12/20 + 5/20 = 17/20
17/20 is not equal to 4/9
Dmitry [639]3 years ago
8 0
Yeah andy is wrong.
3/5 = 12/20
1/4 = 5/20
12/20 + 5/20 = 17/20
17/20 does not = 4/9
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If a dilation is applied to a triangle, then the image must be _____.
netineya [11]

Answer:

a triangle that is rotated about a given point.

Step-by-step explanation:

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3 years ago
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Solve for v.<br> Simplify your answer as much as possible.<br><br> 5+2v=3
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Answer:

v= -1

Step-by-step explanation:

5+2v=3

2v=3-5

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What is the answer??
masha68 [24]
The answer is 30, assuming it is a cube, 
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3 years ago
Find the constant of variation k for the direct variation x -1 0 2 5 f(x) 2 0 -4 -10
Fofino [41]

Answer:

k = -2

Step-by-step explanation:

x     -1   0   2     5

f(x)  2   0  -4  -10

ƒ(x) = kx

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The constant of variation k = -2.

8 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
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