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CaHeK987 [17]
3 years ago
5

Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)

Mathematics
1 answer:
irina1246 [14]3 years ago
4 0

Answer:

Maximize C =9x + 7y

8x + 10y \leq 17

11x + 12y\leq 25

and x ≥ 0, y ≥ 0

Plot the lines on graph

8x + 10y \leq 17

11x + 12y\leq 25

x\geq 0

y\geq 0

So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)

Substitute the points in  Maximize C

At  (0,1.7)

Maximize C =9(0) + 7(1.7)

Maximize C =11.9

At  (2.125,0)

Maximize C =9(2.125) + 7(0)

Maximize C =19.125

At   (0,0)

Maximize C =9(0) + 7(0)

Maximize C =0

So, Maximum value is attained at   (2.125,0)

So, the optimal value of x is 2.125

The optimal value of y is 0

The maximum value of the objective function is 19.125

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What is the length, in units, of segment CD?
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Answer:

The answet is C.

Step-by-step explanation:

First, you have to find the angle of ACB using Sine Rule, sinθ = opposite/hypotenuse :

\sin(θ )  =  \frac{oppo.}{hypo.}

let \: oppo. = 4 \\ let \: hypo. = 5

\sin(θ)  =  \frac{4}{5}

θ = {\sin( \frac{4}{5} ) }^{ - 1}

θ = 53.1 \: (1d.p)

Given that line AB is parallel to line CD so ∠C = 90°. Next, you have to find the angle of ACD :

ACD = 90 - 53.1 = 36.9

Lastly, you can find the length of CD using Cosine rule, cosθ = adjacent/hypotenuse :

\cos(θ)  =  \frac{adj.}{hypo.}

let \: θ = 36.9 \\ let \: adj. = 5 \\ let \: hypo. = CD

\cos(36.9  )  =  \frac{5}{CD}

CD \cos(36.9)  = 5

CD =  \frac{5}{ \cos(36.9) }

CD = 6.25 units\: (3s.f)

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3 years ago
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