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Igoryamba
3 years ago
14

Sorry for asking again but I need help ASAP I will give you 100 points and a brainiest

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer: D. 10.200

Step-by-step explanation:

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I need help with this. I will give brainliest
Vikki [24]

Answer:25

Step-by-step explanation: 2.5x10=25

8 0
3 years ago
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Find the exact value of the indicated trigonometric function of θ.
Mariana [72]

Answer:

cosθ = -√(35/36)

tanθ = -1/√35

Step-by-step explanation:

We know that

sin²θ + cos²θ = 1

(1/6)² + cos²θ = 1

1 - (1/6)² = cos²θ

35/36 = cos²θ

sec θ = 1/ cosθ

1/ secθ = cos θ

Because secθ < 0, 1/ secθ would also be < 0, so cos θ < 0

cosθ = -√(35/36)

tanθ = sinθ/cosθ = (1/6)/-√(35/36)

= (1/6) / -(√35/6)

= -1/√35

8 0
3 years ago
Find a polynomial function of degree 3 with 2, i, -i as zeros.
sergiy2304 [10]

Answer:

p(x)= x^3-2x^2+x-2

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if \alpha , \ \beta \ \& \ \gamma are the zeros of the cubic polynomial , then ,

\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)

Here in place of the Greek letters , substitute 2,i and -i , we get ,

\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

\sf  \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}

Simplify using i = √-1 ,

\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )

Multiply by distribution ,

\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)

Simplify by opening the brackets ,

\sf\longrightarrow p(x)= x^3+x-2x^2-2

Rearrange ,

\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}

4 0
3 years ago
Which expression is equivalent to x + 0.2x​
dangina [55]

Answer:1.2x

Step-by-step explanation:

3 0
3 years ago
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What are the terms of 3x-4xy+10y+1
Juli2301 [7.4K]

Answer:

3x,-4xy,10y,\text{ and }1.

Step-by-step explanation:

Single numbers, variables and product of number and variables are know as terms. In an algebraic expression each term is separated by an addition "+" sign.

The given expression is

3x-4xy+10y+1

It can be written as

3x+(-4xy)+10y+1

Therefore, the terms are 3x,-4xy,10y,\text{ and }1.

8 0
3 years ago
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