Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer:
C
Step-by-step explanation:
5/6=0.83
2/3=0.66
3/5=0.60
11/15=0.73
by changing them to a decimal you get a better look at the amounts they are work and it puts them in a common value.From this you can see that 3/5 is the lowest fraction form the groups so your answer would be <u>C</u>
Answer:
$90 ÷ $2.50 = 36
Massimo rode the bus 36 times.
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