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Deffense [45]
3 years ago
12

Kathleen had a bag of candy-coated chocolates. Of the 55 candies in the bag, 20% were red, 30% were orange, 30% were green, and

20% were blue. Of the blue ones, 10% had a damaged candy coating. Approximately how many of the blue ones had a damaged candy coating?
Mathematics
2 answers:
Elodia [21]3 years ago
5 0
Since there are 55 candies in the bag, and there are 20% of blue candies, it would look like this:

55 x 0.20 = 11

Now that we have 11, you multiply it by the damage coating, so

11 x 0.10 = 1.1
aleksklad [387]3 years ago
4 0
So 20% is 1/5 and 1/5 of 55 is 11. That means there are in total 11 blue candies if 1/5 of them is damaged then technically 2.2 of them are which is kinda weird as it doesn't give whole number
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54 students fit on a bus. There are 125
vfiekz [6]

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125 divided by 54 is 2.31...

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ad-work [718]

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0.18

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Firlakuza [10]
Given:
2 rectangular prism.
same height
square bases


                                    Box A     Box B
Square Base side          2 ft        0.75 ft
Height                            4 ft        4 ft

Solving for the space inside each rectangular prism, we need to find its volume.

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Box B:
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See attachment below
KatRina [158]

Answer: Third Option

x=1.469743

Step-by-step explanation:

We have the following exponential equation

3^{x+1}=15

We must solve the equation for the variable x

To clear the variable x apply the log_3 function on both sides of the equation

log_3(3^{x+1})=log_3(15)

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x+1=log_3(15)

To simplify the expression log_3 (15) we apply the base change property

log_b(y)=\frac{log(y)}{log(b)}

This means that:

log_3 (15)=\frac{log(15)}{log(3)}

Then:

x+1=\frac{log(15)}{log(3)}

x=\frac{log(15)}{log(3)}-1

x=1.469743

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