Answer:
You need at least 125$ so it would be 5x is larger or equal to 125
When solving for x divide both sides by 5
125 / 5 = 25
x = 25
Represent the proportional relationship described with an equation where d equals dogs and c equals cats:
2 answers:
You might be interested in
Answer:
89
Step-by-step explanation:
Hello!
Consecutive integers are whole numbers that are directly after each other.
The first integer can be represented as x, and the next one as x + 1, then x + 2, and lastly x + 3. The sum of all these is equal to 362.
<h3>Solve for x</h3>Since x is the smallest integer in the set, the answer is 89. The other integers would be 90, 91, and 92.
Answer:
ii) a Bonferonni-corrected alpha level of 0.0167 to control the type I error rate for the overall inference to 5% .
Step-by-step explanation:
Previous concepts
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
The hypothesis for this case are:
Null hypothesis:
Alternative hypothesis: Not all the means are equal
Since we reject the null hypothesis we want to see which method it's the best to determine which group(s) is (are) different is pairwise two-sample t-tests each assessed using.
And on this case the best option is:
ii) a Bonferonni-corrected alpha level of 0.0167 to control the type I error rate for the overall inference to 5% .
The reason is because the Bonferroni correction "compensates for that increase by testing each individual hypothesis at a significance level of who represent the desired overall alpha level and m is the number of hypotheses". For our case m=3 hypotheses with a desired
, then the Bonferroni correction would test each individual hypothesis at
One advatange of this method is that "This method not require any assumptions about dependence among the p-values or about how many of the null hypotheses are true" . And is more powerful than the individual paired t tests.