How far apart is 27 and -54

Let f(x) = 2x + 5 and g(x) = x^2 - 3x + 2

denis-greek [22]

Answer:

The answer to your question is below

Step-by-step explanation:

f(x) = 2x + 5

To solve letter a, just multiply each term of f(x) by 3 and subtract 2.

a) 3f(x) - 2 = 3(2x + 5) - 2

= 6x + 15 - 2

= 6x + 13

To f(x) subtract twice g(x)

b) f(x) - 2g(x) = 2x + 5 - 2(x² - 3x + 2)

= 2x + 5 - 2x² + 6x - 4

= -2x² + 8x + 1

Multiply 5 by each term of f(x) and divide it by g(x)

c) $\frac{5f(x)}{g(x)} = \frac{5(2x + 5)}{x^{2} - 3x + 2}$

= $\frac{10x + 25}{x^{2}-3x + 2}$

8 0

3 years ago

1.

worty [1.4K]

The clouds are 226.68 meters above the spotlight.

Step-by-step explanation:

Step 1:

The angle measuring device is 65 meters from the spotlight and the angle of elevation from the ground to the spot of light is 74°.

So a right-angled triangle can be formed using these measurements. The angle of the triangle is 74° while the opposite side of the triangle measures x meters while the adjacent side of the triangle measures 65 meters.

We need to calculate the opposites side's length of the triangle.

Step 2:

Since we have the adjacent side's length and need to calculate the opposite side's length we use the tan of the given angle.

The opposite side of the triangle = x meters.

$\tan \theta = \frac{oppositeside}{adjacentside} = \frac{x}{65}.$