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3 years ago

Solve for a. Assume that a, b, c are not zero. abc=c

Mathematics

2 answers:

Iteru [2.4K]3 years ago

8 0

The answer is C because A and B dont = anything

inn [45]3 years ago

6 0

It is C because a and b are zeros

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krok68 [10]

9. C :)
10. A :)

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3 years ago

Let T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear transformation, and

Klio2033 [76]

Answer:

$\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent set.

Step-by-step explanation:

Given: $\{v_1,v_2,v_3\}$ is a linearly dependent set in set of real numbers R

To show: the set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

Solution:

If $\{v_1,v_2,v_3,...,v_n\}$ is a set of linearly dependent vectors then there exists atleast one $k_i:i=1,2,3,...,n$ such that $k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0$

Consider $k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

A linear transformation T: U→V satisfies the following properties:

1. $T(u_1+u_2)=T(u_1)+T(u_2)$

2. $T(au)=aT(u)$

Here, $u,u_1,u_2$ ∈ U

As T is a linear transformation,

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\$

As $\{v_1,v_2,v_3\}$ is a linearly dependent set,

$k_1v_1+k_2v_2+k_3v_3=0$ for some $k_i\neq 0:i=1,2,3$

So, for some $k_i\neq 0:i=1,2,3$

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

Therefore, set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

6 0

3 years ago

Help plz helpppppppppppp plzzzzzzzzz

zzz [600]

it's 5 days, if you need an explanation feel free

5 0

3 years ago

Read 2 more answers

HELP PLEASE WRITE AWAY

AysviL [449]

The answer is B you divide 0.035 from 16 then subtract that number with 16 with 15.44 you divide it by 0.0425 and with the answer subtract 15.44 with it

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3 years ago

To Mark or decided to purchase a new DVD player on an installment loan DVD player was $295 Tim agreed to pay $31 per month for 1

Verizon [17]

Answer: ⇒ The finance charge = $77

Step-by-step explanation:

Given: The cost price of DVD player= $295

Since, Tim agreed to pay $31 per month for 12 months .

Therefore, the total amount paid by Tim= $31\times12=\$372$