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3 years ago

Solve for a. Assume that a, b, c are not zero. abc=c

Mathematics

2 answers:

Iteru [2.4K]3 years ago

8 0

The answer is C because A and B dont = anything

inn [45]3 years ago

6 0

It is C because a and b are zeros

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3 years ago

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3 years ago

Read 2 more answers

Find the area of rectangle, where length is 15 cm and breadth is 7 cm.

Varvara68 [4.7K]

Question :-

Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

Area of Rectangle is 105 cm² .

$\rule {195pt} {2pt}$

Diagram :-

$\sf{15 \: cm} \\ \quad \quad \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\ \\ \\ \end{array}} \: \: \sf {7 \: cm}\end{gathered}\end{gathered}$

$\rule {195pt} {2pt}$

Solution :-

$\quad \quad$ » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

$\sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}$

Therefore , by Substituting the given values in the above Formula :-

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\$

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}$

$\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}$

Hence :-

Area of Rectangle = 105 cm² .

$\underline {\rule {195pt} {4pt}}$

Additional Information :-

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$