Toniac 123 can you please help me with these questions. They are part of of the question you answered. There is another question
I posted. If you can , can you please help me with both. Thanks and good luck.
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To solve this question, we can start to set up an equation using what the question is telling us. Since we don't know what the number is, let's make it equal to x.
The phrase "5 times a number" means that we're multiplying our unknown, x, by 5. That is equal to 5x. 9 less than that would be 5x - 9. Since we know that it's equal to -30, we can solve.
5x - 9 = -30
Get all terms with x on one side and the constants on the other
5x - 9 +9 = -30 + 9
Simplify
5x = -21
Now, we can divide both sides by 5 to get our answer of x = -
The first term is 612.
The common ratio is 1.08 and
The recursive rule is
<u>Step-by-step explanation:</u>
the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.
<u>The first term :</u>
In geometric sequence, the first term is given as .
⇒
Now, the geometric sequence follows as 612, 661, ........
<u>The common ratio (r) :</u>
It is the ratio between two consecutive numbers in the sequence.
Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.
⇒ r = 661 divided by 612
⇒ r = 1.08
<u>To find the recursive rule :</u>
A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........
Here, first term and other terms are obtained by multiplying by r.
- Observe that each term is r times the previous term.
- Hence to get nth term we multiply (n−1)th term by r .
The recursive rule is of the form
This is called recursive formula for geometric sequence.
We know that r = 1.08 and = 612.
To find the second term , use the recursive rule
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