2x + 5y = -3 ⇒ 2x + 5y = -3
1x + 8y = 4 ⇒ <u>2x + 16y = 8
</u> -<u>11y</u> = <u>-11 </u>
-11 -11
y = 1
2x + 5(1) = -3
2x + 5 = -3
<u> -5 -5</u>
<u>2x</u> = <u>-8</u>
2 2
x = -4
(x, y) = (-4, 1)
2x + 1y = 7 ⇒ 2x + 1y = 7
1x - 2y = -14 ⇒ <u>2x - 4y = -28</u>
<u>5y</u> = <u>35</u>
5 5
y = 7
2x + 7 = 7
<u> -7 -7</u>
<u>2x</u> = <u>0</u>
2 2
x = 0
(x, y) = (0, 7)
1) start with (x-h)^2 + (y-k)^2 = r^2. Insert the given info: center at (-1,8) and radius 5:
(x+1)^2 + (y-8)^2 = 5^2 (answer)
<span>24r - 3(2r - 5t) - 4t
= 24r - 6r + 15t - 4t
= 18r + 11t
answer
</span><span>18r + 11t</span>
Answer:
78.5
Step-by-step explanation:
x3.14 (pie)
so then substitute.
5x5=25
25x3.14=78.5
I'll go out on a limb and suppose you're given the matrix

and you're asked to find the determinant of

, where

and given that

.
There are two properties of the determinant that come into play here:
(1) Whenever a single row/column is scaled by a constant

, then the determinant of the matrix is scaled by that same constant;
(2) Adding/subtracting rows does not change the value of the determinant.
Taken together, we have that