2 years ago

22 POINTS, NEED URGENT HELP

1 answer:

7 0

1) start with (x-h)^2 + (y-k)^2 = r^2. Insert the given info: center at (-1,8) and radius 5:

(x+1)^2 + (y-8)^2 = 5^2 (answer)

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PLEASE THINS IS DUE BY 1 P.M TODAY. PLEASE HELP ME

zaharov [31]

$6 {x}^{2} {y}^{2} (y + 3xy + 6x)$

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3 years ago

(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values

Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

$y=t^2 = (x)^2 = x^2$