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Sonbull [250]
3 years ago
12

Solve Systems by Substitution 2x+5y=-3 x+8y=4 and 2x+y=7 x-2y=-14

Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0
2x + 5y = -3 ⇒ 2x +   5y = -3 
1x + 8y =  4 ⇒ <u>2x + 16y = 8
</u>                               -<u>11y</u> = <u>-11 </u>
                                -11     -11
                                    y = 1
                        2x + 5(1) = -3
                            2x + 5 = -3
                            <u>      -5     -5</u>
                                  <u>2x</u> = <u>-8</u>
                                   2      2
                                    x = -4
                              (x, y) = (-4, 1)

2x + 1y = 7     ⇒ 2x + 1y = 7
1x -  2y = -14 ⇒ <u>2x  - 4y  = -28</u>
                                   <u>5y</u> = <u>35</u>
                                    5      5
                                     y = 7
                             2x + 7 = 7
                             <u>      -7   -7</u>
                                   <u>2x</u> = <u>0</u>
                                    2     2
                                    x = 0
                              (x, y) = (0, 7)
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Equivalent means "equal to"

Because we are looking for an equation that is not equivalent to 3y + x = 18, we need to find one that is not equal to 3y + x = 18.

First, lets try y = 6 - 1/3x

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Then, subtract 1/3x from each side

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Next, lets try y - 5 = -1/3 (x - 3)

First, we need to distribute the -1/3 in the right side.

y - 5 = -1/3x + 1

Add 5 to each side

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Add 1/3x to each side

y + 1/3x = 6

So, y + 1/3x = 6 is NOT equivalent to 3y + x = 18, so it IS an answer.

Lets try the third one: y - 5 = 1/3(x + 3)

We need to use distributive property again on the right side

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Divide the whole of each side by 2

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