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babunello [35]
3 years ago
10

In a rational function, is the horizontal shift represented by the vertical asymptote?

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0
<h3>Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>

A bit of further explanation:

The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.

Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h

For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.

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5x + 2y=7<br> - 2x + 6y=9
ollegr [7]

Answer:

x = \frac{12}{17} or 0.706

y = \frac{59}{34} or 1.735

Step-by-step explanation:

5x + 2y=7    ----->(eq 1)

- 2x + 6y=9 ----->(eq 2)

Multiply (eq 1) with 3

3×(5x + 2y) = 3×7  

15x + 6y = 21  ----->(eq 3)

substract (eq 3) from (eq 2)

- 2x + 6y - (15x + 6y) = 9-21

- 2x + 6y - 15x - 6y = 9-21

- 2x - 15x + 6y - 6y = 9-21

-17x = -12

x = -12 ÷ -17

x = \frac{12}{17}

put x = \frac{12}{17} in (eq 1)

5*\frac{12}{17} + 2y = 7

2y = 7- 5*\frac{12}{17}

2y = \frac{7*17 - 60}{17}

2y = \frac{119- 60}{17}

2y = \frac{59}{17}

y = \frac{59}{17*2}

y = \frac{59}{34}

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4 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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