3 years ago

Write this as a decimal 92.8% a. 9280 b. 92.8 c. 0.928 d. 9.28

Mathematics

1 answer:

stepladder [879]3 years ago

7 0

The answer would be C. 0.928.

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The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the e

n200080 [17]

Center of the circle: C=(3,8)=(h,k)→h=3, k=8
Radius of the circle: r=5
Standard form of the equation for the circle:
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-8)^2=5^2
(x-3)^2+(y-8)^2=25

General for of the equation for the circle:
(x)^2-2(x)(3)+(3)^2+(y)^2-2(y)(8)+(8)^2=25
x^2-6x+9+y^2-16y+64=25
x^2+y^2-6x-16y+73=25
x^2+y^2-6x-16y+73-25=25-25
x^2+y^2-6x-16y+48=0

Answer: The general form of the equation for the circle is:
x^2+y^2-6x-16y+48=0

4 0

4 years ago

Write an equation for the line in point-slope and slope-intercept forms.

kobusy [5.1K]

point-slope form: y-y₁ = m(x-x₁)

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$\rightarrow \sf y - 5 = \dfrac{5}{3} (x-3)$

slope-intercept form: y = mx + b

============

$\rightarrow \sf y - 5 = \dfrac{5}{3}(x)+ \dfrac{5}{3}(-3)$

$\rightarrow \sf y - 5 = \dfrac{5}{3}(x)-5$

$\rightarrow \sf y = \dfrac{5}{3}(x)-5+5$

$\rightarrow \sf y = \dfrac{5}{3}(x)$

6 0

3 years ago

Read 2 more answers

+4.31. Let a(s) be a unit speed curve with kt = 0. Prove there is a curve

yanalaym [24]

Answer:

It is proved

Step-by-step explanation:

A curve immersed in the three-dimensional sphere is said to be a Bertrand curve if there exists another curve and a one-to-one correspondence between and such that both curves have common principal normal geodesics at corresponding points.

See attachment for the step by step solution of the given problem.