Answer:
x = -1.04, x= 1.03 and x=3.
Step-by-step explanation:
To find the zeros of the function, we need to factorize the function x^62+4x-12.
Using Wolfram alpha, we find that the function only has TWO real roots:
x = -1.04 and x= 1.03.
Therefore, the roots of g(x) are:
x = -1.04, x= 1.03 and x=3.
if x = x0 is a root of g(x), then g(x0) = 0. So, let's prove that those are the roots:
g(-1.04) = ((-1.04)^62+4(-1.04)-12)((-1.04)-3) = 0
g(-1.03) = ((-1.03)^62+4(-1.03)-12)((-1.03)-3) = 0
g(3) = ((3)^62+4(3)-12)((3)-3) = 0